扭曲过滤器将变量移出其环境 [英] Warp filter moving variable out of its environment
问题描述
我正在尝试实现一个过滤器,该过滤器位于我的所有路由中并提取标头并将可能的令牌与系统上存储的内容相匹配.
I am trying to implement a filter that sits in all my routes and extracts a header and matches a possible token to what is stored on my system.
我想实现类似扭曲拒绝示例 但我收到错误
I want to implement something like the warp rejection example but I get the error
期望一个实现 Fn
trait 的闭包,但是这个闭包只实现 FnOnce
闭包是 FnOnce
因为它移动了变量 tmp
脱离其环境
expected a closure that implements the
Fn
trait, but this closure only implementsFnOnce
closure isFnOnce
because it moves the variabletmp
out of its environment
我有点明白编译器在说什么,但不知道如何解决.我认为做 let tmp = store.clone()
会.
I kind of get what the compiler saying, but don't know how to solve it.
I thought doing let tmp = store.clone()
would.
我有过滤器:
pub fn haystack_auth_header(store: Store) -> impl Filter<Extract = (Store,), Error = Rejection> + Clone {
let tmp = store.clone();
warp::header("Authorization").and_then (|auth_header: String| async move {
// Authorization: BEARER authToken=xxxyyyzzz
let result = auth_token(&auth_header); //-> IResult<&'a str, (&'a str, &'a str), (&'a str, ErrorKind)> {
if result.is_err() {
return Err(reject::custom(HayStackAuthToken));
}
let (_, key_value) = result.unwrap();
let auth_token_result = tmp.read().get_authtoken();
if auth_token_result.is_err() {
return Err(reject::custom(HayStackAuthToken));
}
let auth_token_option = auth_token_result.unwrap();
if auth_token_option.is_none() {
return Err(reject::custom(HayStackAuthToken));
}
let auth_token = auth_token_option.unwrap();
if auth_token != key_value.1 {
return Err(reject::custom(HayStackAuthToken));
}
Ok(tmp)
})
}
store
是 type Store = Arc
并且 UserAuthStore
是 trait UserAuthStore: fmt::Debug + Send + Sync
.
store
is type Store = Arc<RwLock<Box<dyn UserAuthStore>>>
and UserAuthStore
is trait UserAuthStore: fmt::Debug + Send + Sync
.
UserAuthStore 定义为
UserAuthStore is defined as
pub trait UserAuthStore: fmt::Debug + Send + Sync {
// Return handshake token for username. If user has no handshake token generate one
fn get_handshake_token(&self, username: &str) -> HaystackResult<String>;
fn get_username(&self, handshake_token: &str) -> HaystackResult<String>;
fn set_temporary_value(&mut self, k: &str, v: &str) -> HaystackResult<()>;
fn get_temporary_value(&self, k: &str) -> HaystackResult<Option<&String>>;
fn set_authtoken(&mut self, s: String) -> HaystackResult<()>;
/// returns a base64 encoded sha256 salt of password.
fn get_password_salt(&self) -> HaystackResult<String>;
fn get_salted_password(&self) -> HaystackResult<String>;
fn get_authtoken(&self) -> HaystackResult<Option<String>>;
}
为什么 clone
在这里不起作用?
Why does clone
not work here?
完整的错误是
error[E0525]: expected a closure that implements the `Fn` trait, but this closure only implements `FnOnce`
--> src/server/mod.rs:997:45
|
997 | warp::header("Authorization").and_then (|auth_header: String| async move {
| ___________________________________--------__^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^_-
| | | |
| | | this closure implements `FnOnce`, not `Fn`
| | the requirement to implement `Fn` derives from here
998 | |
999 | | // Authorization: BEARER authToken=xxxyyyzzz
1000 | | let result = auth_token(&auth_header); //-> IResult<&'a str, (&'a str, &'a str), (&'a str, ErrorKind)> {
... |
1026 | | Ok(tmp.clone())
1027 | | })
| |_____- closure is `FnOnce` because it moves the variable `tmp` out of its environment
推荐答案
在创建了一个简单的测试用例之后,我设法使用以下函数让它运行起来.
After creating a simple test case I managed to get it going with the following function.
pub fn haystack_auth_header(store: Store) -> impl Filter<Extract = (Store,), Error = Rejection> + Clone {
warp::header("Authorization").and_then (
move |auth_header: String|
{
let tmp = store.clone();
async move {
let tmp = tmp.clone();
if tmp.read().get_authtoken().is_none() {
return Err(reject::custom(HayStackAuthToken));
}
Ok(tmp.clone())
}
}
)
}
所以最后只需要在正确的位置克隆.
So in the end just needed clone in the correct place.
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