对于循环和停止条件 [英] For Loops and stopping conditions

问题描述

任何人都可以解释为什么答案是他们想要的吗?我猜第一个是因为已经达到停止条件，所以它跳过了该语句，但问题13为什么它不打印4321?

Can anyone explain why the answers are what they are please? The first one i guess its because the stopping condition is already reached so it skips the statement but question 13 why would it not print 4321?

12.以下代码产生什么输出:

int n;
for (n = 1; n > 4; n++)
    System.out.print(n); 

a)12345

b)1234

c)0 ---> for循环永远不会运行，因为已经满足停止条件.

c) 0 ---> for loop never runs because stopping condition already met.

d)它不产生输出*

d) It produces no output*

13.以下代码产生什么输出:

int n;
for (n = 4; n > 0; n--);  
    System.out.print(n); 

a)43210

b)4321

c)0 * ---> for循环后为半冒号，导致print语句在循环结束后运行

c) 0* ---> semi colon after for loop, causing print statement to run after loop is finished

d)它不产生输出

推荐答案

关于问题13:for循环后面有分号.因此，循环将首先执行，直到n不再> 0 =>然后为零为止.然后，打印结果将显示为零.

Regarding question 13: there's a semicolon behind the for-loop. Because of that, the loop will first be execuetd until n no longer is > 0 => it is zero then. Then, the print will show a zero.

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