以功能方式组合谓词 [英] Combining predicates in a functional way

问题描述

Boost Hana是否提供将谓词与逻辑运算符组合的方法?

Does Boost Hana provide a way to combine predicates with logical operators?

我指的是这样的东西

constexpr auto both = [](auto&& f, auto&& g){
    return [&f,&g](auto&& x){ return f(x) && g(x); };
};

可以这样使用:

int main() {
    std::vector<int> v{1,2,3,4,5,6,7,8,9,10};
    auto less_than_7 = hana::reverse_partial(std::less_equal<int>{}, 7);
    auto more_than_3 = hana::reverse_partial(std::greater_equal<int>{}, 3);
    auto r = ranges::views::remove_if(v, both(less_than_7, more_than_3));
}

在Hana，我希望还有一种以类似

where, from Hana, I'd expect also a way to use it in an infix way similar to hana::on, as in both(less_than_7, more_than_3) === less_than_7 ^both^ more_than_3 (even though and would be nicer, but I've just found that it's a synonym for &&).

或者它是否提供一种解除标准运算符&& 以便在函数函子上进行操作的方法?

Or maybe does it offer a way to lift the standard operator && to operate on function functors?

推荐答案

您可以使用

You could use demux like:

auto both = hana::demux(std::logical_and<bool>{});
// Or for any number of predicates
auto all = hana::demux([](auto const&... x) noexcept(noexcept((static_cast<bool>(x), ...))) { return (true && ... && static_cast<bool>(x)); });
ranges::views::remove_if(v, both(less_than_7, more_than_3));

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