运行awk脚本后截断字符串 [英] Truncation of strings after running awk script

问题描述

我有这个代码

BEGIN { FS=OFS=";" }
{ key = $(NF-1) }
NR == FNR {
    for (i=1; i<(NF-1); i++) {
        if ( !seen[key,$i]++ ) {
            map[key] = (key in map ? map[key] OFS : "") $i
        }
    }
    next
}
{ print $0 map[key] }

我以这种方式使用代码

awk -f tst.awk 2.txt 1.txt

我有两个文本文件

1 .txt

AA;BB;

2 .txt

CC;DD;BB;AA;

我尝试生成此 3 .txt输出

I try to generate this 3.txt output

AA;BB;CC;DD;

但无法使用此脚本，因为此脚本仅返回 AA; BB;

but with this script is not possible because this script return only AA;BB;

逻辑:上面的代码仅在数组索引的哈希查找中使用文字字符串，因此它不在乎输入中包含哪些字符.但是关于示例输出:
如果在 2 .txt中， 1 .txt中也有一些公共字段，例如 BB; AA; 那么您需要将它们连接在一行中，即 AA; BB; CC; DD; 不需要排序，例如，如果输出为 BB; AA; DD; CC;
唯一需要的条件是避免重复，但是我的脚本已经这样做了

logic: The above just uses literal strings in a hash lookup of array indices so it doesn't care what characters you have in your input. However about sample output:
if in 2.txt there are common fields also in 1.txt.for example BB;AA; then you need concatenate them in a single row, i.e AA;BB;CC;DD; Ordering is not required, for example is not relevant if output is BB;AA;DD;CC;
Only condition that is required is avoid duplicates but my script already does this

推荐答案

能否请您尝试以下操作，根据OP的注释，两个文件只有1行.因此，使用 paste 命令合并两个文件，然后通过 awk 命令处理其输出.

Could you please try following, as per OP's comment both files have only 1 line. So using paste command to combine both the files and then processing its output by awk command.

paste -d';' 1.txt 2.txt | 
awk '
BEGIN{
  FS=OFS=";"
}
{
  for(i=1;i<=NF;i++){
    if(!seen[$i]++){ val=(val?val OFS:"")$i }
  }
  print val
  delete seen
  val=""
}'

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