如何在不使用依赖注入的情况下从另一个包中模拟一个函数? [英] How do I mock a function from another package without using dependency injection?

问题描述

有点像golang的初学者，但是我之前已经使用过测试框架.我该如何模拟并伪造从属方法返回的结果而不注入该从属关系?我不想使用依赖项注入的原因是因为有许多外部包方法正在使用，并且将所有方法注入构造函数中都很麻烦.

Somewhat of a golang beginner, but I've worked with testing frameworks before. How do I go about mocking out and faking what a dependent method returns without injecting the dependency? The reason why I don't want to use dependency injection is because there are many external package methods that are being used and injecting all of the methods in the constructor is unwieldy.

我已经搜索了此在线/堆栈溢出，并且解决方案是始终使用依赖项注入.有时这不是一个可行的选择.

I've searched for this online/stackoverflow and the solution is to always use dependency injection. Sometimes that is not a viable option.

这就是我要在代码方面做的事情:

Here's what I'm trying to do code-wise:

b/b_test.go

b/b_test.go

package b

func TestResults(t *testing.T) {
    t.Run("Test", func(t *testing.T) {
        b := NewB()
        // How do I mock out and fake a.DoSomething() to be
        // "complete" instead of whats in the code right now?
        result = b.Results()
        assert.Equal(t, "complete", result)            
    }
}

b/b.go

package b

import "a"

type B struct {}

func NewB() B {
    return &B{}
}

func (b B) Results() {
    return a.DoSomething()
}

a/a.go

package a

func DoSomething() {
    return "done"
}

谢谢！

推荐答案

您可以使用使用构建标签进行条件编译

a/a.go

// +build !mock

package a
func DoSomething() {
    return "done"
}

a/a_mock.go

a/a_mock.go

// +build mock

package a
func DoSomething() {  // Insert fake implementation here
    return "complete"
}

$ 去测试-tags模拟

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