为什么要使用&在结构上签名? [英] Why should I use the & sign on structs?

问题描述

在getour中，有一个部分:结构文字.

In the gotour, there is a section: struct literals.

package main

import "fmt"

type Vertex struct {
    X, Y int
}

var (
   v1 = Vertex{1, 2}  // has type Vertex
   v2 = Vertex{X: 1}  // Y:0 is implicit
   v3 = Vertex{}      // X:0 and Y:0
   p  = &Vertex{1, 2} // has type *Vertex
)

func main() {
   fmt.Println(v1, p, v2, v3)
}

带&"的结构与不带&"的结构有什么区别?我知道那些带有&符的引用指向相同的参考，但是为什么我要在普通的引用符上使用它们呢?

What's the difference between a struct with an ampersand and the one without? I know that the ones with ampersands point to the same reference, but why should I use them over the regular ones?

 var p = &Vertex{} // why should I use this
 var c = Vertex{} // over this

推荐答案

注释几乎说明了这一点:

The comments pretty much spell it out:

   v1 = Vertex{1, 2}  // has type Vertex
   p  = &Vertex{1, 2} // has type *Vertex

与许多其他语言一样，& 获取地址后跟的标识符.当您想要一个指针而不是一个值时，这很有用.

As in many other languages, & takes the address of the identifier following it. This is useful when you want a pointer rather than a value.

如果您需要了解有关编程中指针的更多信息，则可以从此，甚至维基百科页面.

If you need to understand more about pointers in programming, you could start with this for go, or even the wikipedia page.

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