确保URI有效 [英] Ensure a URI is valid

问题描述

我正在尝试确保传递给go程序的URL有效.但是，我似乎无法解决.我以为我可以通过 url.Parse 喂它，但这似乎没用.

I'm trying to ensure that URLs passed to my go program are valid. However, I can't seem to work out how to. I thought I could just feed it through url.Parse, but that doesn't seem to do the job.

package main

import (
    "fmt"
    "net/url"
)

func main() {
    url, err := url.Parse("http:::/not.valid/a//a??a?b=&&c#hi")
    if err != nil {
        panic(err)
    }
    fmt.Println("It's valid!", url.String())
}

游乐场

我可以使用 filter_var 的内容吗?

推荐答案

您可以检查您的URL是否具有Scheme，Host和/或Path.

You can check that your URL has a Scheme, Host, and/or a Path.

如果检查返回的URL，则可以看到无效部分已插入不透明数据部分(从某种意义上讲，它是有效的).

If you inspect the URL returned, you can see that the invalid part is inserted into the Opaque data section (so in a sense, it is valid).

url.URL{Scheme:"http", Opaque:"::/not.valid/a//a", Host:"", Path:"", RawQuery:"?a?b=&&c", Fragment:"hi"}

如果您解析一个URL并且没有Scheme，Host和Path，您可能会认为它无效.(尽管没有路径的主机通常可以，因为它暗示/，所以您需要检查一下)

If you parse a URL and don't have a Scheme, Host and Path you can probably assume it's not valid. (though a host without a path is often OK, since it implies /, so you need to check for that)

u, err := url.Parse("http:::/not.valid/a//a??a?b=&&c#hi")
if err != nil {
    log.Fatal(err)
}

if u.Scheme == "" || u.Host == "" || u.Path == "" {
    log.Fatal("invalid URL")
}

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