爪哇 - 字符串转换为有效的URI对象 [英] Java - Convert String to valid URI object

问题描述

我想从一个字符串 A java.net.URI中对象。串具有一定的字符，这将需要通过百分比转义序列来替换。但是当我使用URLEn codeR为en code使用UTF-8编码字符串，就连/被替换为它们的转义序列。

I am trying to get a java.net.URI object from a String. The string has some characters which will need to be replaced by their percentage escape sequences. But when I use URLEncoder to encode the String with UTF-8 encoding, even the / are replaced with their escape sequences.

我怎样才能得到一个有效的连接codeD URL从一个String对象？

How can I get a valid encoded URL from a String object?

http://www.google.com?q=ab 提供的的http％3A％2F％2www.google.com ... ，而我需要的输出为 http://www.google.com?q=a%20b

http://www.google.com?q=a b gives http%3A%2F%2www.google.com... whereas I want the output to be http://www.google.com?q=a%20b

有人能告诉我如何做到这一点。

Can someone please tell me how to achieve this.

我试图做到这一点在Android应用程序。所以，我有机会获得库的数量有限。

I am trying to do this in an Android app. So I have access to a limited number of libraries.

推荐答案

您可以试试： org.apache.commons.httpclient.util.URIUtil.en codeQuery 在阿帕奇公地httpclient的项目

这样的（见<一href="http://svn.apache.org/viewvc/httpcomponents/oac.hc3x/trunk/src/java/org/apache/commons/httpclient/util/URIUtil.java?view=markup">URIUtil):

URIUtil.encodeQuery("http://www.google.com?q=a b")

将变成：

http://www.google.com?q=a%20b

当然你也可以自己做，但URI解析可以得到pretty的凌乱......

You can of course do it yourself, but URI parsing can get pretty messy...

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