杜松子酒通配符路线与现有孩子发生冲突 [英] Gin wildcard route conflicts with existing children

问题描述

我想构建一个 gin 程序，有以下路线:

I'd like to build a gin program which serves the following routes:

r.GET("/special", ... // Serves a special resource.
r.Any("/*", ...       // Serves a default resource.

但是，这样的程序在运行时会出现紧急情况:

However, such a program panics at runtime:

[GIN-debug] GET    /special                  --> main.main.func1 (2 handlers)
[GIN-debug] GET    /*                        --> main.main.func2 (2 handlers)
panic: wildcard route '*' conflicts with existing children in path '/*'

是否可以创建一个gin程序，该程序为每个路由除了的一个默认资源，而为单个路由提供一个不同的资源?

Is it possible to create a gin program which serves a default resource for every route except for a single one which serves a different resource?

Web上的许多页面使我相信无法使用默认的gin路由器，那么从gin程序提供这些路由的最简单方法是什么?

Many pages on the web lead me to believe it is not possible using the default gin router, so what is the easiest way to serve these routes from a gin program?

推荐答案

在gin.NoRoute()无法接受的情况下，也许其他人(例如我)会收到此错误消息.我从github上获取了以下代码 对于此问题:

Maybe someone else (like me) will have this error message in a situation where gin.NoRoute() won't be an acceptable fix. I took the following code from github in search for a workaround for this issue:

    router.GET("/v1/images/:path1", GetHandler)           //      /v1/images/detail
    router.GET("/v1/images/:path1/:path2", GetHandler)    //      /v1/images/<id>/history

func GetHandler(c *gin.Context) {
    path1 := c.Param("path1")
    path2 := c.Param("path2")

    if path1 == "detail" && path2 == "" {
        Detail(c)
    } else if path1 != "" && path2 == "history" {
        imageId := path1
        History(c, imageId)
    } else {
        HandleHttpError(c, NewHttpError(404, "Page not found"))
    }
}

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