四舍五入到Golang中的所有小数点 [英] Round all decimal points in Golang

问题描述

我试图以非常规方式将float64变量中的所有数字四舍五入.例如:

I'm trying to unconventionally round all the digits in a float64 variable. For example:

3.4444445-> 3.5

3.4444445 --> 3.5

我想做到这一点而不将其转换为字符串！

I want to do this without converting it into a string!

推荐答案

Golang的数学库提供了 Round 函数.但是，它将float64舍入为一个int，这意味着会丢失小数.

Golang's math library provides a Round function. However, it rounds the float64 to an int, meaning decimals are lost.

对此的快速解决方法是将数字乘以要保存的小数位数，然后四舍五入，然后再除以:

A quick workaround around this would be to multiple the number by the number of decimals you want to save, then round, then divide it back again:

raw := 4.335
rounded := math.Round(raw * 10) / 10

会给您想要的结果.

您可能想要创建一个小助手功能来舍入保存任意数量的数字:

You may want to create a little helper function to round saving any number of digits:

func roundTo(n float64, decimals uint32) float64 {
  return math.Round(n*math.Pow(10, float64(decimals))) / math.Pow(10, float64(decimals))
}

用法:

roundTo(4.2655, 1) // 4.3
roundTo(4.3454, 3) // 4.345

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