在 C# 中四舍五入到小数点后两位 [英] Rounding up to 2 decimal places in C#

问题描述

我有一个十进制数，可能如下所示:

I have a decimal number which can be like the following:

189.182

我想把这个向上四舍五入到小数点后两位，所以输出如下:

I want to round this up to 2 decimal places, so the output would be the following:

189.19

在 Math 类中是否有内置的功能或其他功能?我知道天花板函数存在，但这似乎不是我想要的 - 它会四舍五入到最近的整数，所以在这种情况下只是189".

Is there built in functionality for this in the Math class, or something else? I know the ceiling function exists but this doesn't seem to do what I want - it'll round to the nearest int, so just '189' in this case.

推荐答案

乘以 100，调用天花板，除以 100 做我认为你要求的事情

Multiply by 100, call ceiling, divide by 100 does what I think you are asking for

public static double RoundUp(double input, int places)
{
    double multiplier = Math.Pow(10, Convert.ToDouble(places));
    return Math.Ceiling(input * multiplier) / multiplier;
}

用法如下:

RoundUp(189.182, 2);

这是通过将小数点向右移动 2 位(因此它位于最后 8 位的右侧)然后执行上限运算，然后将小数点移回其原始位置来实现的.

This works by shifting the decimal point right 2 places (so it is to the right of the last 8) then performing the ceiling operation, then shifting the decimal point back to its original position.

这篇关于在 C# 中四舍五入到小数点后两位的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！