在Swift中将数字四舍五入至小数点后两位 [英] Round a digit upto two decimal place in Swift
本文介绍了在Swift中将数字四舍五入至小数点后两位的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在获取一个数字值,我试图将其转换为两位小数.但是当我将其转换为结果0.00时.这些数字是 0.24612035420731018
.当获得其.2f值时,它显示为0.00.我尝试过的代码是这样,
I'm getting a value of digits which i'm trying to convert to two decimal places. But when i convert it it makes the result to 0.00 . The digits are this 0.24612035420731018
. When get its .2f value it shows 0.00. The code that i tried is this,
let digit = FindResturantSerivce.instance.FindResModelInstance[indexPath.row].distance
let text = String(format: "%.2f", arguments: [digit])
print(text)
推荐答案
使用格式字符串将其舍入到小数点后两位,并将双精度数转换为字符串:
Use a format string to round up to two decimal places and convert the double to a String:
let currentRatio = Double (rxCurrentTextField.text!)! / Double (txCurrentTextField.text!)!
railRatioLabelField.text! = String(format: "%.2f", currentRatio)
示例:
let myDouble = 3.141
let doubleStr = Double(String(format: "%.2f", myDouble)) // 3.14
let myDouble = 3.141
let doubleStr = String(format: "%.2f", myDouble) // "3.14"
如果您想将小数点后一位四舍五入,可以执行以下操作:
If you want to round up your last decimal place, you could do something like this :
let myDouble = 3.141
let doubleStr = Double(String(format: "%.2f", ceil(myDouble*100)/100)) // 3.15
let myDouble = 3.141
let doubleStr = String(format: "%.2f", ceil(myDouble*100)/100) // "3.15"
这篇关于在Swift中将数字四舍五入至小数点后两位的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文