AppleScript的;在空间数N打开应用 [英] Applescript; opening an app in Space number N

问题描述

我不知道是否有可能在AppleScript的创建，我们给作为输入应用程序名称和一个数N的脚本，所以这个应用程序获取空间的空间数量N.打开

I wonder if it is possible in applescript to create a script for which we give as input the application name and a number N, so this app gets opened in the Space's space number N.

我想这个想创建一个荟萃的AppleScript，所以当计算机启动和登录后，每个空间，我得到不同的应用程序，而重要的是，我可以在脚本文件改变这一点，而不是通过Mac OS X的空间的preferences

I would like with this to create a meta-applescript, so when the computer boots and after login, on each space I get different apps, and important, I can change this in the script file, and not through mac os x Space's preferences

感谢

推荐答案

在OS X 10.5或10.6，空格任务可接，并通过编写脚本的界面来修改系统Events.app <​​/ code>：

In OS X 10.5 or 10.6, Spaces assignments can be accessed and changed via the scriptable interface to System Events.app:

tell application "System Events"
    set x to application bindings of spaces preferences of expose preferences
    set x to {|com.apple.textedit|:4} & x  -- Have TextEdit appear in space 4
    set application bindings of spaces preferences of expose preferences to x
end tell

如果你不知道的话，你可以从Finder中的应用程序的捆绑ID：

If you don't already know it, you can get the bundle id of an application from the Finder:

tell application "Finder"
    get id of application file "TextEdit" of folder "Applications" of startup disk
end tell

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