Visual Studio调试器：打破进入一个外部函数？ [英] Visual Studio debugger: Break on entering an external function?

问题描述

使用只是我的code 关闭，源位置/服务器，很容易步入的功能是不是在你的code。有没有一种方法来设置一个断点其中之一，虽然？

With "Just My Code" turned off and a source location/server, it's easy to step into functions that are not in your code. Is there a way to set a breakpoint on one of these, though?

基本上，我想说时，这个功能是从任何地方调用，突破和给我的来源。我尝试了设置函数断点，并输入功能的完全限定名称，但它说，它无法找到的功能。

Basically, I want to say "when this function is called from anywhere, break and show me the source". I tried the "set function breakpoint" and entering the fully-qualified name of the function, however it said it couldn't find the function.

推荐答案

我理解了它的感谢精彩的博客文章的 <一个href="http://www.aaronlerch.com/blog/2007/08/31/tip-set-breakpoints-without-source-$c$c-in-visual-studio-2005/"相对=nofollow>提示：没有源$ C ​​$ C在Visual Studio中设置断点2005 的

I figured it out thanks to the wonderful blog post TIP: Set breakpoints without source code in Visual Studio 2005.

即使它报告说未找到方法，它仍然会出现突破，一旦组件被加载（假设你的拼写方法正确;-P）。

Even though it reports that the method wasn't found, it will still break there once the assembly is loaded (assuming you spelled the method right ;-P).

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