Visual Studio调试器：打破输入外部函数？ [英] Visual Studio debugger: Break on entering an external function?

问题描述

使用仅我的代码关断和一个源位置/服务器，很容易进入不在代码中的功能。有没有办法在其中一个设置断点？

With "Just My Code" turned off and a source location/server, it's easy to step into functions that are not in your code. Is there a way to set a breakpoint on one of these, though?

基本上，我想说当这个函数从任何地方调用时，打破并显示我资源。我尝试了设置功能断点并输入功能的完全限定名称，但是它表示找不到该功能。

Basically, I want to say "when this function is called from anywhere, break and show me the source". I tried the "set function breakpoint" and entering the fully-qualified name of the function, however it said it couldn't find the function.

推荐答案

由于精彩的博客文章，我想出了这个结果 提示：在Visual Studio 2005中设置没有源代码的断点 。

I figured it out thanks to the wonderful blog post TIP: Set breakpoints without source code in Visual Studio 2005.

即使它报告没有找到该方法，一旦加载程序集（假定您拼写方法正确; -P），它仍然会在那里崩溃。

Even though it reports that the method wasn't found, it will still break there once the assembly is loaded (assuming you spelled the method right ;-P).

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