scanf一个大的十六进制值 [英] scanf a big hexadecimal value

问题描述

我尝试使用scanf从用户那里获取一个大的十六进制数字(12个字符)时遇到问题.

I have a issue trying to use scanf to get a big hexadecimal num (12 chars) from the user.

似乎只能获取最后8个字符，例如-ABFFFFFFFF将变为0000FFFFFFFF.

it seems to only get the last 8 chars, eg - ABFFFFFFFF will become 0000FFFFFFFF.

这是我的代码-

unsigned long long address;
scanf("%x",&address);
printf("Address: %#014x", address);

对于此输入:"ABFFFFFFFF"，输出为:

for this input: "ABFFFFFFFF" the output would be:

地址:0x0000ffffffff

Address: 0x0000ffffffff

我尝试过用scanf格式播放，但无济于事.

i have tried playing a bit with the scanf format, but to no avail.

推荐答案

scanf格式和printf都必须使用％llx".有关更多详细信息，请参见手册页.

You must use "%llx" for both scanf format and printf. See the manual page for additional details.

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