将一个十六进制拆分为2个十六进制值 [英] Spliting an hex into 2 hex values

问题描述

我有一个问题，我有一个十六进制的 0x6002 ，我必须将其拆分为 0x60 和 0x02 。
我该怎么做？

I have a problem I have an Hexadecimal like 0x6002 and I have to split it into 0x60 and 0x02. how do I do that?

我在cpp中编程，必须与网络端口进行通信。为此，我有一个地址必须在中间分开，我的问题是我将十六进制存储在 Uint8 中，将数字转换为小数。我该如何解决我的问题？

I progam in cpp and have to communicate with a network port. For that I have an address which I have to split in the middle my issue is that I store the hex in a Uint8 wich converts the number to a decimal. how can i solve my problem?

推荐答案

uint16_t port = 0x6002;
uint8_t high = (port >> 8) & 0xFF;
uint8_t low = port & 0xFF;

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