十六进制到整数(4个字节) [英] Hex to integer (4 bytes)

问题描述

我正在使用ZigBee，我从终端设备的传感器接收数据，并且希望将十六进制转换为整数.数据来自4bytes，该信息与电池有关，我得到的一个例子是:"00 00 00 e1"(但无空格)，我需要将此传递给电压，但首先我想我需要将其传递给int.

I'm working with ZigBee, I receive data from a sensor of a end device, and I want to convert from hex to int. The data are from 4bytes, this information is regarding the battery, an example of what I get would be this: "00 00 00 e1" (but without blanks) and I need to pass this on to voltages, but first I think I need to pass it to int.

任何人都可以帮助我吗?我正在为Android开发应用程序.

Anyone can help me please? I'm doing my application for Android.

谢谢.

推荐答案

int n = (int)Long.parseLong(st.replaceAll("\\s+",""), 16);

(其中st是您的字符串)可以执行此操作.两件事:

(where st is your string) does it. Two things:

replaceAll 会删除任何空白.

我通过 Long 解析器绕过 NumberFormatExceptions 否定项

I go via the Long parser to circumvent NumberFormatExceptions for negatives

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