URLSearchParams为第一个查询字符串返回null [英] URLSearchParams returning null for the first query string

问题描述

为什么时间段为空

const url = 'http://example.com?timeperiod=lasttwentyeightdays&pagesize=20'
const args =  new URLSearchParams(url);
alert('timeperiod='+args.get('timeperiod') + ' and pagesize='+ args.get('pagesize'));

但是在下面的代码中它可以工作

But in the below code it works

  const url = 'http://example.com?x=c&timeperiod=lasttwentyeightdays&pagesize=20'
  const args =  new URLSearchParams(url);
  alert('timeperiod='+args.get('timeperiod') + ' and pagesize='+ args.get('pagesize'));

推荐答案

您应该创建一个URL对象，然后使用url.search检索参数:

You are supposed to create an URL object and then retrieve the params with url.search : https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams/URLSearchParams#Examples

const url = new URL('http://example.com?timeperiod=lasttwentyeightdays&pagesize=20');

const args =  new URLSearchParams(url.search);

console.log(`timeperiod=${args.get('timeperiod')} and pagesize=${ args.get('pagesize')}`);

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