如何将itemscope拆分为多个HTML元素? [英] How to split itemscope over multiple HTML elements?
问题描述
我有以下HTML:
<body itemscope itemtype="http://schema.org/WebPage">
<header itemscope itemtype="http://schema.org/WPHeader">
<nav itemscope itemtype="http://schema.org/SiteNavigationElement">
</nav>
...
<div itemscope itemtype="http://schema.org/Organization" itemref="objectDetails">
<span itemprop="name">Org name</span><br>
<span itemprop="address" itemscope itemtype="http://schema.org/PostalAddress">
...
</span>
</div>
</header>
<ul itemprop="breadcrumb" itemscope itemtype="http://schema.org/BreadcrumbList">
<li itemprop="itemListElement" itemscope itemtype="http://schema.org/ListItem">..</li>
...
</ul>
<div id="objectDetails">
<div itemprop="description">...</div>
<div itemprop="foundingDate">...</div>
...
</div>
</body>
此网页显示有关一个特定组织的信息.有关组织的某些信息应显示在页面标题中，其他信息应显示在页面中心.借助 itemref 属性，我可以拆分有关组织的信息，并将其放在两个单独的div上.
This web page displays information about one particular organization. Some information about organization should be displayed in a page header, other - in the center of a page. With the help of itemref attribute I can split information about organization and put it on two separate divs.
如果我使用google结构化数据测试工具测试以上HTML，它会正确提取有关组织的信息，但会显示两个div的属性，但会在WebPage对象上显示验证错误:
If I test the above HTML with google structured data testing tool - it extracts info about organization correctly - properties from both divs are shown, but it shows validation error on a WebPage object:
对于类型为
WebPage的对象，Google无法识别属性foundingDate.
The property
foundingDateis not recognized by Google for an object of typeWebPage.
告诉Google，objectDetails div内部的属性不属于外部itemscope(WebPage)的正确方法是什么?如果我将 itemscope itemtype ="http://schema.org/Organization" 添加到objectDetails div中，则Google会在我的网页上看到两个独立的组织.
What is the correct way to tell Google that properties that are inside objectDetails div doesn't belong to the outer itemscope (WebPage)? If I add itemscope itemtype="http://schema.org/Organization" to objectDetails div - then Google sees two separate organizations on my WebPage.
推荐答案
这是不可能的.
可能的解决方案":
-
请勿在容器"上使用任何物品，例如
html或body.在不涵盖全部内容的元素上使用它，并在需要时使用itemref.
Don’t use an item on a "container" like
htmlorbody. Use it on an element that doesn’t span the whole content, and useitemrefif needed.
使用多个项目，并在 itemid 中为它们指定相同的URI.但是，尚不清楚是否/何时/如何/Schema.org如何支持 itemid ，以及来自消费者可能是坏人.
Use multiple items and specify the same URI in itemid for them. However, it’s not clear if/when/how Schema.org supports itemid, and support from consumers is probably bad.
(使用使用RDFa代替微数据自然可以做到这一点.)
(Using RDFa instead of Microdata would allow this naturally.)
向包含不想添加到原始父项的所有属性的元素中添加未类型化的项(通过添加没有 itemtype 的 itemscope ).示例: 1 ， 2 ， 3 .
Add an untyped item (by adding an itemscope without itemtype) to the element containing all properties you don’t want to add to the original parent item. Examples: 1, 2, 3.
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