如何将句子拆分为多个空格分隔的单词? [英] How to split sentence into words separated by multiple spaces?

问题描述

以下代码:

val sentence = "1 2  3   4".split(" ")

给我:

Array(1, 2, "", 3, "", "", 4)

但我宁愿只有单词:

Array(1, 2, 3, 4)

当单词被多个空格分隔时，如何拆分句子?

How can I split the sentence when the words are separated by multiple spaces?

推荐答案

使用正则表达式:

scala> "1   2 3".split(" +")
res1: Array[String] = Array(1, 2, 3)

+"表示前一个或多个"(前一个是空格).

The "+" means "one or more of the previous" (previous being a space).

更好的是，如果您想在所有空白处进行拆分:

Better yet, if you want to split on all whitespace:

scala> "1   2 3".split("\\s+")
res2: Array[String] = Array(1, 2, 3)

(其中 "\\s" 是 模式 匹配任何空格.查看这里 获取更多示例.)

(Where "\\s" is a Pattern which matches any whitespace. Look here for more examples.)

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