如何将一串空格分隔的数字拆分为整数? [英] How to split a string of space separated numbers into integers?
问题描述
我有一个字符串 "42 0"
(例如)并且需要获取两个整数的数组.我可以在空间上做一个 .split
吗?
使用 <代码>str.split():
<预><代码>>>>"42 0".split() # 或 .split(" ")['42', '0']请注意,str.split(" ")
在这种情况下是相同的,但如果一行中有多个空格,则行为会有所不同.同样,.split()
拆分所有空白,而不仅仅是空格.
使用 map
通常看起来比使用列表推导式更简洁,当您想将可迭代项转换为诸如 int
、float
之类的内置函数时、str
等.在 Python 2 中:
在 Python 3 中,map
将返回一个惰性对象.您可以使用 list()
将其放入列表:
I have a string "42 0"
(for example) and need to get an array of the two integers. Can I do a .split
on a space?
Use str.split()
:
>>> "42 0".split() # or .split(" ")
['42', '0']
Note that str.split(" ")
is identical in this case, but would behave differently if there were more than one space in a row. As well, .split()
splits on all whitespace, not just spaces.
Using map
usually looks cleaner than using list comprehensions when you want to convert the items of iterables to built-ins like int
, float
, str
, etc. In Python 2:
>>> map(int, "42 0".split())
[42, 0]
In Python 3, map
will return a lazy object. You can get it into a list with list()
:
>>> map(int, "42 0".split())
<map object at 0x7f92e07f8940>
>>> list(map(int, "42 0".split()))
[42, 0]
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