如何将带有任何空格字符的字符串拆分为分隔符？ [英] How do I split a string with any whitespace chars as delimiters?

问题描述

我需要使用什么正则表达式模式传递给 java.lang.String.split（）方法，以使用所有空格字符将String拆分为子串数组（ ''，'\ t'，'\ n'等等）作为分隔符？

解决方案

行中的东西of

  myString.split（\\\\ +）; 
  

这会将所有空格分组为分隔符。

所以如果我有字符串：

Hello [space] [tab] ]世界

这应该产生字符串Hello和World并省略 [space] 和 [tab] 。

正如VonC指出的那样，反斜杠应该被转义，因为Java会首先尝试将字符串转义为特殊字符，并发送那个要解析。你想要的是文字\ s，这意味着你需要传递\\\\。它可能会有点混乱。

\\\\ 相当于 [\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

What regex pattern would need I to pass to the java.lang.String.split() method to split a String into an Array of substrings using all whitespace characters (' ', '\t', '\n', etc.) as delimiters?

解决方案

Something in the lines of

myString.split("\\s+");

This groups all white spaces as a delimiter.

So if I have the string:

"Hello[space][tab]World"

This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab].

As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send that to be parsed. What you want, is the literal "\s", which means, you need to pass "\\s". It can get a bit confusing.

The \\s is equivalent to [ \\t\\n\\x0B\\f\\r]

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