字母等级"D"，"C-"，...，"A +"的Pythonic自定义排序? [英] Pythonic custom sort for letter grades 'D', 'C-' ,..., 'A+'?

问题描述

是否有比这更复杂的Pythonic，紧凑，直观的方式来对字母等级进行排序(不使用自定义字典)?

Is there a more Pythonic, compact, intuitive way to sort letter-grades than this (without using a custom dict)?

grades = ['B-','C','B','C+','A','D+','B+','C-','A+','D','A-']

sorted(grades, key=lambda g: (g[0], '+ -'.index((g+' ')[1])) )

['A+', 'A', 'A-', 'B+', 'B', 'B-', 'C+', 'C', 'C-', 'D+', 'D']

为了获得'X-'，'X'，'X +'的比较数字顺序，我做了一个空格''的hacky追加，以便 g [1] 始终存在，因此我可以使用 .index()来获取修饰符'+-'的排名.

In order to get the comparative numerical order of 'X-','X','X+', I do a hacky append of a space ' ' so that g[1] always exists, so then I can use .index() to get the rank of the modifier '+ -'.

(由此问题所激励)

推荐答案

否.

modmap = {
  '-': 0,
  '': 1,
  '+': 2
}

print(sorted(grades, key=lambda x: (-ord(x[0]), modmap[x[1:]])))

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