您如何从文件中读取n个字节并将其放入vector <uint8_t>中?使用迭代器? [英] How do you read n bytes from a file and put them into a vector&lt;uint8_t&gt; using iterators?

问题描述

基于此问题:

如何将二进制文件读入无符号字符的向量中

答案是:

std::vector<BYTE> readFile(const char* filename)
{
    // open the file:
    std::basic_ifstream<BYTE> file(filename, std::ios::binary);

    // read the data:
    return std::vector<BYTE>((std::istreambuf_iterator<BYTE>(file)),
                              std::istreambuf_iterator<BYTE>());
}

将整个文件读入向量.

我要执行的操作是一次(例如)在向量中读取100个字节，然后执行填充操作，然后将接下来的100个字节读取到向量中(清除之间的向量).我看不到如何指定要读取的文件数量(即如何设置迭代器).那有可能吗?

What I want to do is read (for example) 100 bytes at a time in the vector, then do stuff, and then read the next 100 bytes into the vector (clear the vector between). I don't see how to specify how much of the file to read (i.e. how to setup the iterators). Is that even possible?

我试图避免编写自己的代码循环来一次复制每个字节.

I am trying to avoid having to write my own code loop to copy each byte at a time.

推荐答案

您可以为此使用 ifstream :: read .

std::vector<BYTE> v(100);
while ( file.read(reinterpret_cast<char*>(v.data()), 100) )
{
   // Find out how many characters were actually read.
   auto count = file.gcount();

   // Use v up to count BTYEs.
}

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