坐标周围的C ++数组总和值 [英] C++ Array Sum Values Around Coordinate

问题描述

我在汇总下面给出的坐标周围的多维数组的值时遇到了一些困难.我的索引位置逻辑有问题.任何想法都将非常有帮助，如果需要更多信息，请随时问我.

I'm having some difficulty summing the values of a multidimensional array around the coordinates given below. Something is wrong with my logic with the index location. Any ideas would be very helpful and if more information is needed, please don't hesitate to ask me.

#include <iostream>
#include <ctime>


using namespace std;

int main()
{
srand(time(0));

int displayArray[11][11];

    cout<<"\t\t\t\t\t\t\t\t\t\t\t\t\tColumn\n\n";
    for(int column=1;column<10;column++)
    {
        cout<<"\t "<<column;
    }
    cout<<"\n\n";
    //fill array with random numbers

    for(int i=0;i<9;i++)
    {
        for(int m=0;m<9;m++)
        {
            displayArray[i][m]=rand()%10;
        }
    }

    cout<<"\n\n\n";

    //main data printout

    for(int k=0;k<9;k++)
    {
        cout<<"Row "<<k+1<<"\t ";

    for(int l=0;l<9;l++)
    {
        cout<<displayArray[k][l]<<"\t";
    }
    cout<<endl<<endl;
    }

    cout<<"\n\n";

    int row=0, column=0;
    cout<<"What array cell would you like to see? (Press enter after each entry)\n";
    cout<<"Row = ";
    cin>>row;
    cout<<"Column = ";
    cin>>column;
    cout<<"\nThe number "<<displayArray[row-1][column-1]<<" is in cell "<<row<<","<<column;

    int coord1=displayArray[row-2][column+2],
        coord2=displayArray[row+2][column+2],
        coord3=displayArray[row-2][column-2],
        coord4=displayArray[row-2][column+2],
        coord5=displayArray[row-2][column+2],
        coord6=displayArray[row-2][column+2],
        coord7=displayArray[row-2][column+2],
        coord8=displayArray[row-2][column+2];

    int sum=coord1+coord2+coord3+coord4+coord5+coord6+coord7+coord8;

    cout<<"\n\nThe sum of the cells surrounding "<<row<<","<<column<<" is "<<sum;

    cin.get();
    cin.get();


return 0;
}

推荐答案

您的问题可能是您将row/column -2和row/column +2用作相邻方向，这是不正确的.如果(row-1，col-1)是当前单元格，则您希望row/col -2和row/col +0.

Your problem may be that you are using row/column -2 and row/column +2 as your adjacent directions, which is not correct. If (row-1, col-1) is your current cell, than you want row/col -2 and row/col +0.

int coord1=displayArray[row-2][column-2],
    coord2=displayArray[row-2][column-1],
    coord3=displayArray[row-2][column],
    coord4=displayArray[row-1][column-2],
    coord5=displayArray[row-1][column],
    coord6=displayArray[row][column-2],
    coord7=displayArray[row][column-1],
    coord8=displayArray[row][column];
int sum=coord1+coord2+coord3+coord4+coord5+coord6+coord7+coord8;

这可以通过编程来完成，但是:

This can be done much more programmatically, however:

int sum = 0;
for (int x=row-2; x<=row; x++) {
    for (int y=column-2; y<=column; y++) {
        if ((x != row-1) || (y != column-1)) { //Avoids "center" cell (self)
            sum += displayArray[x][y]
        }
    }
}

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