write()接受2个位置参数，但给出了3个 [英] write() takes 2 positional arguments but 3 were given

问题描述

当我使用 print()函数在屏幕上打印它们时，我的程序可以正确产生所需的结果:

My program produces the desired results correctly as I print them on the screen using the print() function:

for k in main_dic.keys():
    s = 0
    print ('stem:', k)
    print ('word forms and frequencies:')
    for w in main_dic[k]:
        print ('%-10s ==> %10d' % (w,word_forms[w]))
        s += word_forms[w]
    print ('stem total frequency:', s)

    print ('------------------------------')

我想将结果以准确的格式写入文本文件.我尝试了这个:

I want to write the results with the exact format to a text file though. I tried with this:

file = codecs.open('result.txt','a','utf-8')
for k in main_dic.keys():
    file.write('stem:', k)
    file.write('\n')
    file.write('word forms and frequencies:\n')
    for w in main_dic[k]:
        file.write('%-10s ==> %10d' % (w,word_forms[w]))
        file.write('\n')
        s += word_forms[w]
    file.write('stem total frequency:', s)
    file.write('\n')
    file.write('------------------------------\n')
file.close()

但是我得到了错误:

TypeError:write()接受2个位置参数，但给出了3个

TypeError: write() takes 2 positional arguments but 3 were given

推荐答案

print()采用单独的参数，而 file.write() 则没有.您可以重复使用 print()改为写入您的文件:

print() takes separate arguments, file.write() does not. You can reuse print() to write to your file instead:

with open('result.txt', 'a', encoding='utf-8') as outf:
    for k in main_dic:
        s = 0
        print('stem:', k, file=outf)
        print('word forms and frequencies:', file=outf)
        for w in main_dic[k]:
            print('%-10s ==> %10d' % (w,word_forms[w]), file=outf)
            s += word_forms[w]
        print ('stem total frequency:', s, file=outf)
        print ('------------------------------')

我还使用了内置的 open()，因此无需在Python 3中使用较旧且通用性较低的 codecs.open().也不需要调用 .keys()，直接在字典上循环也可以.

I also used the built-in open(), there is no need to use the older and far less versatile codecs.open() in Python 3. You don't need to call .keys() either, looping over the dictionary directly also works.

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