Javascript正则表达式再次捕获 [英] Javascript regex multiple captures again
问题描述
好的，我想我需要重新发布最初是我的问题:
Ok, I think I need to repost my question that was originally:
带有完整的示例.我有:
with a full example. I have:
var text = ""+
"<html> " +
" <head> " +
" </head> " +
" <body> " +
" <g:alert content='alert'/> " +
" <g:alert content='poop'/> " +
" </body> " +
"</html>";
var regex = /<([a-zA-Z]*?):([a-zA-Z]*?)\s([\s\S]*?)>/m;
var match = regex.exec( text );
console.log(match)
console.log的输出为:
问题是我只得到第一个结果...别的……我该怎么做才能捕获并遍历所有匹配的东西?
The problem is that I am only getting the result for the first ... not the other... what can I do to be able to capture and walk over all stuff that matched?
推荐答案
exec 一次仅返回一个结果，并将指针设置为该匹配的结尾.因此，如果要获得所有匹配项，请使用 while 循环:
exec returns only ONE result at a time and sets the pointer to the end of that match. Therefore, if you want to get ALL matches use a while loop:
while ((match = regex.exec( text )) != null)
{
console.log(match);
}
要一次获得所有匹配，请使用 text.match(regex)，其中正则表达式指定了 g (全局标志). g 标志将使 match 查找字符串中与正则表达式的所有匹配项，并在数组中返回所有匹配项.
To get all matches at one shot, use text.match(regex), in which the regex has g (global flag) specified. The g flag will make match find all matches to the regex in the string and return all the matches in an array.
这就是为什么我的示例设置了g标志！[/eoe]
[edit] and that's why my example HAD a g flag set! [/eoe]
var text = ""+
"<html> " +
" <head> " +
" </head> " +
" <body> " +
" <g:alert content='alert'/> " +
" <g:alert content='poop'/> " +
" </body> " +
"</html>";
// Note the g flag
var regex = /<([a-zA-Z]*?):([a-zA-Z]*?)\s([\s\S]*?)>/gm;
var match = text.match( regex );
console.log(match);
简单测试:
<button onclick="myFunction()">Try it</button>
<script>
function myFunction()
{
var text = ""+
"<html> " +
" <head> " +
" </head> " +
" <body> " +
" <g:alert content='alert'/> " +
" <g:alert content='poop'/> " +
" </body> " +
"</html>";
// Note the g flag
var regex = /<([a-zA-Z]*?):([a-zA-Z]*?)\s([\s\S]*?)>/gi;
var n = text.match( regex );
alert(n);
}
</script>
工作完美...
这篇关于Javascript正则表达式再次捕获的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
