为什么要懒惰?强制序列化期间初始化? [英] Why Lazy<T> forces initialization during serialization?

问题描述

当我检查Lazy < T> 类的实现时，我看到了以下代码块:

When I checked the implementation of Lazy<T> class, I saw this block:

[OnSerializing]
private void OnSerializing(StreamingContext context)  
{  
     T obj = this.Value;  
} 

如您所见，它在序列化过程中强制初始化.有谁知道为什么将这种行为作为默认设置?

As you can see it's forcing initialization during serialization. Does anyone know why this behavior is preferred as default?

推荐答案

如果没有，并且您提供了lambda进行初始化，那么您认为它在哪里反序列化了呢?Lambda无法序列化.

if it doesnt and you provided lambda for initialization, where do you think it retrives the value on deserializing? lambdas are not serializable.

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