使用C ++在Linux中的输出字符串覆盖终端上的最后一个字符串 [英] output string overwrite last string on terminal in Linux with c++
问题描述
说我有一个命令行程序.有没有办法让我说
Say I have a command line program. Is there a way so that when I say
std::cout << stuff
如果我不执行 std :: cout<<'\ n'
在另一个 std :: cout<<之间; ,,,,,,,的其他输出将覆盖同一行的最末尾的东西(清理行)?
if I don't do a std::cout << '\n'
in between another std::cout << stuff
, another output of stuff will overwrite the last stuff on the same line (cleaning the line) starting at the leftmost column?
我认为 ncurses 有能力这?如果可能的话,我可以说 std :: cout<<std :: overwrite<<东西
I think ncurses has the ability to do this? If possible, it would be great if I could say std::cout << std::overwrite << stuff
其中 std :: overwrite
是某种iomanip.
Where std::overwrite
is some sort of iomanip.
推荐答案
您是否尝试过回车 \ r
?这应该做您想要的.
Have you tried carriage returns \r
? This should do what you want.
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