检查单词是否在列表中，该值是字典的值 [英] Check if a word is in a list that is a value of a dictionary

问题描述

我正在尝试检查单词是否在列表中，该列表是字典的值.例如，我想检查'noodles'是否在: {1:['hello'，'hallo'，'salut'，'ciao'，'hola']，2:['eggs'，'noodles'，'bacon']}

我尝试过:

  element ='noodles'myDict.values()中的元素 

但是我得到: False

解决方案

您的代码检查 element ('noodles')是否是字典中的值，并且不是(值是列表).

您需要检查每个列表中是否包含 element .

如果您不关心密钥，则:

  print(any(myDict.values()中value的值元素) 

如果您想知道密钥(这将打印出匹配密钥的列表):

  print([用于键的键，如果值中包含元素，则为myDict.items()中的值]) 

但是，通常来说，如果您发现自己不得不一遍又一遍地遍历字典，则可能是错误地选择了哪些键，或者完全使用了错误的数据结构.

I'm trying to check if a word is in a list that is a value of a dictionary. For example i want to check if 'noodles' is in: {1:['hello', 'hallo', 'salut', 'ciao', 'hola'], 2:['eggs', 'noodles', 'bacon']}

I tried with:

element = 'noodles'
element in myDict.values()

But i get: False

解决方案

Your code checks if element ('noodles') is a value in the dictionary, and it isn't (the values are lists).

You need to check if element is inside every list.

If you don't care for the key:

print(any(element in value for value in myDict.values()))

If you want to know the key (this will print a list of matching keys):

print([key for key, value in myDict.items() if element in value])

But, generally speaking, if you find yourself having to loop over a dictionary over and over again, you either made a bad choice for what are the keys, or using the wrong data structure altogether.

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