Python:检查任何列表元素是否是字典中的键 [英] Python: Check if any list element is a key in a dictionary

问题描述

给定以下代码

all_options = { "1": "/test/1", "2": "/test/2", "3": "/test/3" }selected_options = [ "1", "3" ]

如何从 all_options 中获取键与 selected_options 中的条目匹配的条目?

我开始使用列表推导式，但我被困在最后一个子句上:

final = ()[ final.append(option) for option in all_options if ... ]

谢谢

解决方案

就是这样?

<预><代码>>>>dict((option, all_options[option]) for option in selected_options if option in all_options){'1': '/test/1', '3': '/test/3'}

从 Python 2.7 和 3 开始，您可以使用 dict 理解 语法:

{option : all_options[option] for option in selected_options if option in all_options}

或者，如果您只想要这些值:

<预><代码>>>>[all_options[option] for selected_options 中的选项如果 all_options 中的选项]['/test/1', '/test/3']

Given the following code

all_options = { "1": "/test/1", "2": "/test/2", "3": "/test/3" }
selected_options = [ "1", "3" ]

How do I get the entries from all_options where the key matches an entry in selected_options?

I started down the path of using a List Comprehension, but I'm stuck on the last clause:

final = ()
[ final.append(option) for option in all_options if ... ]

Thank you

解决方案

Just like this?

>>> dict((option, all_options[option]) for option in selected_options if option in all_options)
{'1': '/test/1', '3': '/test/3'}

From Python 2.7 and 3 onwards, you can use the dict comprehension syntax:

{option : all_options[option] for option in selected_options if option in all_options}

Or if you just want the values:

>>> [all_options[option] for option in selected_options if option in all_options]
['/test/1', '/test/3']

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