用Lodash删除对象属性 [英] Removing object properties with Lodash

问题描述

我必须删除与我的模型不匹配的不需要的对象属性.如何用Lodash实现它?

I have to remove unwanted object properties that do not match my model. How can I achieve it with Lodash?

我的模特是:

var model = {
   fname: null,
   lname: null
}

在发送到服务器之前，我的控制器输出为:

My controller output before sending to the server will be:

var credentials = {
    fname: "xyz",
    lname: "abc",
    age: 23
}

如果我使用

 _.extend(model, credentials)

我也获得了年龄财产.我知道我可以使用

I am getting the age property too. I am aware I can use

delete credentials.age

但是，如果我有10个以上不需要的对象，该怎么办?我可以用Lodash实现吗?

but what if I have more than 10 unwanted objects? Can I achieve it with Lodash?

推荐答案

使用model 获取属性列表#keys"rel =" noreferrer> _.keys() ，然后使用 _.pick() 将属性从凭据提取到新对象:

Get a list of properties from model using _.keys(), and use _.pick() to extract the properties from credentials to a new object:

var model = {
   fname:null,
   lname:null
};

var credentials = {
    fname:"xyz",
    lname:"abc",
    age:23
};

var result = _.pick(credentials, _.keys(model));

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.16.4/lodash.min.js"></script>

如果您不想使用Lodash，则可以使用

If you don't want to use Lodash, you can use Object.keys(), and Array.prototype.reduce():

var model = {
   fname:null,
   lname:null
};

var credentials = {
    fname:"xyz",
    lname:"abc",
    age:23
};

var result = Object.keys(model).reduce(function(obj, key) {
  obj[key] = credentials[key];
  return obj;
}, {});

console.log(result);

这篇关于用Lodash删除对象属性的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！