从对象的所有键中删除字符(Lodash OK) [英] Remove Characters from All Keys in an Object (Lodash OK)

问题描述

在此对象中的所有键之前，我都有一个令人讨厌的字符长度.由于它们都是相同的，所以我想做一个 .map()或 forEach()或一个带有 .slice()的东西在其中删除前 n 个字符.如何对对象中的所有键进行此操作?

I have a bothersome length of characters before all keys in this object. Since they are all the same, I would like to do a .map() or forEach() or something with a .slice() in it to remove the first n characters. How is this done to all keys in the object?

我应该说我们已经在项目中导入了Lodash，所以我可以使用它.

I should say that we are already importing Lodash in the project so I can use that.

所以我需要把这个转过来:

So I need to turn this:

{
  'remove.this.string.a': "apple",
  'remove.this.string.b': "banana",
  'remove.this.string.c': "carrot",
  'remove.this.string.d': "diakon"
}

并将其转换为:

{
  "a": "apple",
  "b": "banana",
  "c": "carrot",
  "d": "diakon"
}

推荐答案

使用object.entries获取键和值.循环更改密钥.

Use object.entries to get the keys and values. Loop over changing the key.

直接更改对象

var obj = {
  'remove.this.string.a': "apple",
  'remove.this.string.b': "banana",
  'remove.this.string.c': "carrot",
  'remove.this.string.d': "diakon"
}

// Object.entries(obj).forEach(function(arr) {
//   var key = arr[0]
//   var value = arr[1]
//   delete obj[key]
//   obj[key.split(".").pop()] = value
// })
Object.entries(obj).forEach(([key, value]) => {
  delete obj[key]
  obj[key.split(".").pop()] = value
})

console.log(obj)

或减少以创建新对象

var obj = {
  'remove.this.string.a': "apple",
  'remove.this.string.b': "banana",
  'remove.this.string.c': "carrot",
  'remove.this.string.d': "diakon"
}

// const updated = Object.entries(obj).forEach(function(obj, arr) {
//   var key = arr[0]
//   var value = arr[1]
//   obj[key.split(".").pop()] = value
//   return obj
// }, {})
const updated = Object.entries(obj).reduce((obj, [key, value]) => {
  obj[key.split(".").pop()] = value
  return obj
}, {})

console.log(updated)

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