如果对象中的属性不存在,如何从数组中删除对象 [英] How to remove object from array if property in object do not exist

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本文介绍了如果对象中的属性不存在,如何从数组中删除对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下数据收集

[{
 id: '1',
 date: '2017-01-01',
 value: 2
 },
 {
 id: '2',
 date: '2017-01-02',
 value: 3
 },
 {
 id: '3',
 value: 3
 },
 id: '4',
 date: '2017-01-02',
 value: 3
 }]

我想删除任何不具有'date'属性的对象.在上面的示例中,应删除ID为3的对象.

I want to delete any object that does not have the 'date' property. In the example above, the object with the id 3 should be deleted.

完成的对象应该看起来像这样

The finished object should look like this

[{
 id: '1',
 date: '2017-01-01',
 value: 2
 },
 {
 id: '2',
 date: '2017-01-02',
 value: 3
 },
 id: '4',
 date: '2017-01-02',
 value: 3
 }]

我试图用lodash查找和删除一个未定义的值.这没用.该对象看起来与输入的对象完全一样.

I tried to find and delete a undefined value with lodash. It does not work. The object looks exactly as it is entering.

  _.each(obj, (val) => {
    _.remove(val, value => value['XXX-BUDAT'] === undefined);
   });

我该如何使用lodash?

How can I use lodash for this purpose?

预先感谢

推荐答案

您可以使用

You can use .filter(), Object.keys(), and .includes()

let input = [
   { id: '1', date: '2017-01-01', value: 2},
   { id: '2', date: '2017-01-02', value: 3},
   { id: '3', value: 3 },
   { id: '4', date: '2017-01-02', value: 3 }
]
 
 let output = input.filter(obj => Object.keys(obj).includes("date"));
 
 console.log(output);

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