“结合" 2正则表达式与逻辑还是? [英] “combine” 2 regex with a logic or?

问题描述

我有两种javascript模式:

I have two patterns for javascript:

/^ [A-z0-9] {10} $/-长度为10个字母数字符号的字符串.

/^[A-z0-9]{10}$/ - string of exactly length of 10 of alphanumeric symbols.

和

/^ \ d + $/-至少长度为1的任意数量.

/^\d+$/ - any number of at least length of one.

10 或任意数字的 OR 字符串如何表达?

How to make the expression of OR string of 10 or any number?

var模式=/^([A-z0-9] {10})|(\ d +)$/;

由于某种原因无法正常工作.至少可以通过

doesn't work by some reason. It passes at lest

pattern.test("123kjhkjhkj33f");  // true  

这不是数字，也不是 A-z0-9 字符串的10个长度.

which is not number and not of length of 10 for A-z0-9 string.

推荐答案

请注意，您的 ^([A-z0-9] {10})|(\ d +)$ 模式匹配10个字符在字符串开头的 A-z0-9 范围内( ^ 仅修改([A-z0-9] {10})部分(第一个替代分支)，或(< | )在带有(\ d +)$ ($ 仅修改(\ d +)分支模式.

Note that your ^([A-z0-9]{10})|(\d+)$ pattern matches 10 chars from the A-z0-9 ranges at the start of the string (the ^ only modifies the ([A-z0-9]{10}) part (the first alternative branch), or (|) 1 or more digits at the end of the stirng with (\d+)$ (the $ only modifies the (\d+) branch pattern.

还请注意， Az 是一个错字， [Az] 确实会不仅匹配ASCII字母.

Also note that the A-z is a typo, [A-z] does not only match ASCII letters.

您需要按如下方式修复它:

You need to fix it as follows:

var pattern = /^(?:[A-Za-z0-9]{10}|\d+)$/;

或使用 i 修饰符:

var pattern = /^(?:[a-z0-9]{10}|\d+)$/i;

请参见 正则表达式演示 .

请注意，分组在这里很重要:(?:... | ...)使锚点适当地应用于每个锚点.

Note that grouping is important here: the (?:...|...) makes the anchors apply to each of them appropriately.

详细信息

• ^ -字符串的开头
• (?:-一个非捕获交替组:
  • [A-Za-z0-9] {10} -10个字母数字字符
  • | -或
  • \d+ - 1 位或更多位
  • ^ - start of string
  • (?: - a non-capturing alternation group:
    • [A-Za-z0-9]{10} - 10 alphanumeric chars
    • | - or
    • \d+ - 1 or more digits

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