使用sed在句点后插入空格 [英] Insert space after period using sed

问题描述

我有一堆文件的句子结尾是这样的: \ @.下一个句子.我想在句点之后插入一个空格.

I've got a bunch of files that have sentences ending like this: \@.Next sentence. I'd like to insert a space after the period.

并非所有出现的 \ @.都没有空格，因此我的正则表达式检查句点后的下一个字符是否为大写字母.

Not all occurrences of \@. do not have a space, however, so my regex checks if the next character after the period is a capital letter.

因为我要在句点之后检查一个字符，所以我不能仅将 \ @.替换为 \ @.，并且因为我没有不知道接下来的角色是什么，我被困住了.

Because I'm checking one character after the period, I can't just do a replace on \@. to \@., and because I don't know what character is following the period, I'm stuck.

我当前的命令:

sed -i .bak -E 's/\\@\.[A-Z]/<SOMETHING IN HERE>/g' *.tex

如何获取匹配字符串的最后一个字母以用于替换正则表达式?

How can I grab the last letter of the matching string to use in the replacement regex?

为了记录，我使用的是 sed 的BSD版本(我使用的是OS X)-来自我的

For the record, I'm using a BSD version of sed (I'm using OS X) - from my previous question regarding sed, apparently BSD sed (or at least, the Apple version) doesn't always play nice with GNU sed regular expressions.

推荐答案

正确的命令应为:

sed -i.bak -E "s/\\\@.(\S)/\\\@. \1/g" *.tex

在此情况下，您匹配任何 \ @ ，后跟非空格( \ S )，然后插入空格(将整个匹配项替换为'\ @'加上刚刚找到的非空格.

Whith it, you match any \@ followed by non whitespace (\S) and insert a whitespace (what is made by replacing the whole match with '\@ ' plus the the non whitespace just found).

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