如何在networkx中更漂亮地绘制一棵树 [英] How to draw a tree more beautifully in networkx

问题描述

如果我使用networkx制作一棵树并将其绘制，则节点重叠.有没有办法画出来所以没有重叠?

 将matplotlib.pyplot导入为plt将networkx导入为nxT = nx.generators.balanced_tree(2，5)nx.draw(T)plt.show()

解决方案

我不是这方面的专家，但这里的代码使用了 pydot 库及其 graph_viz依赖性.这些库随 Anaconda Python 一起提供，但默认情况下未安装，因此请先从命令提示符执行此操作:

conda 安装 pydot

然后，这里的代码改编自

或者，如果您更喜欢自顶向下的树，您可以将代码中的字符串 "twopi" 替换为 "dot"，并且如果您使结果窗口变宽

此外，如果您使用字符串"circo" 并扩大窗口范围，则会得到

If I make a tree using networkx and draw it, the nodes overlap. Is there a way to draw it so there is no overlap?

import matplotlib.pyplot as plt
import networkx as nx
T = nx.generators.balanced_tree(2, 5)
nx.draw(T)
plt.show()

解决方案

I am no expert in this, but here is code that uses the pydot library and its graph_viz dependency. These libraries come with Anaconda Python but are not installed by default, so first do this from the command prompt:

conda install pydot

Then here is code adapted from Circular Tree.

import matplotlib.pyplot as plt
import networkx as nx
import pydot
from networkx.drawing.nx_pydot import graphviz_layout

T = nx.balanced_tree(2, 5)

pos = graphviz_layout(T, prog="twopi")
nx.draw(T, pos)
plt.show()

If you adjust the window to make it square, the result is

Or, if you prefer a top-down tree, you could replace the string "twopi" in that code with "dot", and if you make the resulting window wider you get

Also, if you use the string "circo" instead and make the window wider, you get

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