在圆上生成点 [英] Generating points on a circle

问题描述

import random
import math
import matplotlib.pyplot as plt


def circle():
    x = []
    y = []
    for i in range(0,1000):
        angle = random.uniform(0,1)*(math.pi*2)
        x.append(math.cos(angle));
        y.append(math.sin(angle));
    plt.scatter(x,y)
    plt.show()
circle()

我写了上面的代码在单位圆上随机绘制1000个点.但是，当我运行这段代码时，由于某种原因，它绘制了一个椭圆形.这是为什么?

I've written the above code to draw 1000 points randomly on a unit circle. However, when I run this code, it draws an oval for some reason. Why is this?

推荐答案

It is a circle -- 问题是轴的纵横比不是 1，所以绘制时看起来像椭圆.要获得 1 的纵横比，您可以使用:

It is a circle -- The problem is that the aspect ratio of your axes is not 1 so it looks like an oval when you plot it. To get an aspect ratio of 1, you can use:

plt.axes().set_aspect('equal', 'datalim')  # before `plt.show()`

这在演示中突出显示.

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