递增数组值 - 的Arduino [英] Incrementing array values - Arduino

问题描述

我想增加一些数组值：

  INT计数器[] = {0,0,0,0,0,0,0,0};
 

如果数目在位置0值达到25，然后在1位的值被加1，并且位置0复位为0等等 - 当索引位置2到25它加1的位置3，并复位它自己的值改为0。

我做了一些base26递增 - 生成的字母一个字母给定数量的所有组合。理想情况下，我想这无限的工作（理论上） - 一个新的数组索引追加当最后一个值达到25

我正在此previous问题涉及到项目 - 可能澄清我想要做的事： Every字母表长达29个字符的排列？ 的

这里的code我在一分钟：

  //设置变量。
字符串新词;
INT计数器[] = {0,0,0,0,0,0,0,0};
字符串base26 [] = {\"a\",\"b\",\"c\",\"d\",\"e\",\"f\",\"g\",\"h\",\"i\",\"j\",\"k\",\"l\",\"m\",\"n\",\"o\",\"p\",\"q\",\"r\",\"s\",\"t\",\"u\",\"v\",\"w\",\"x\",\"y\",\"z\"};无效设置（）{
    //初始化串口通信：
    Serial.begin（9600）;
}空隙环（）{
    INT I = 0;
    //重置或增加计数器。
    如果（计数[一] == 25）{
        计数器由[i] = 0;
        计数器[I + 1] ++;
    }
    其他{
        计数器[I] ++;
    }
    新词=字母（计数器[I]）;
    Serial.print（+新词新义的'\\ n'）;
    延迟（100）;
    我++;
    如果（ⅰ大于7）{
        I = 0;
    }
}包含字母（INT计数器）{
    串newword;
    的for（int i = 0; I＆LT; = 7;我++）{
        newword + = base26 [窗口];
    }
    返回newword;
}
 

解决方案

使用的类java.math.BigInteger中。

I'm trying to increment some array values:

int counter[] = {0,0,0,0,0,0,0,0};

If the value of the number in position 0 reaches 25, then the value in position 1 is incremented by 1, and position 0 reset to 0. And so on - when index position 2 reaches 25 it increments position 3 by 1, and resets it's own value to 0.

I'm doing some base26 incrementing - generating all the combinations of letters for a given number of letters. Ideally I'd like this to work infinitely (in theory) - a new array index is appended when the last value reaches 25.

I'm working on the project which this previous question relates to - might clear up what I'm trying to do: Every permutation of the alphabet up to 29 characters?

Here's the code I have at the minute:

// Set the variables.
String neologism;
int counter[] = {0,0,0,0,0,0,0,0};
String base26[] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

void setup() {
    // Initialize serial communication:
    Serial.begin(9600);
}

void loop() {
    int i = 0;
    // Reset or increment the counter.
    if (counter[i] == 25) {
        counter[i] = 0;
        counter[i+1]++;
    }
    else {
        counter[i]++;
    }
    neologism = letters(counter[i]);
    Serial.print(neologism+'\n');
    delay(100);
    i++;
    if(i>7) {
        i=0;
    }
}

String letters(int counter) {
    String newword;
    for(int i=0; i <= 7; i++) {
        newword += base26[counter];
    }
    return newword;
}

解决方案

Use class java.math.BigInteger.

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