在 Matplotlib 中隐藏轴外的区域 [英] Hide area outside of axis in Matplotlib

问题描述

如何扩展绘图区域以占据整个画布并从根本上去除图像中的灰色区域?我环顾四周，但没有找到任何解决方案，尽管可能是因为我不知道该区域的名称，所以搜索非常困难.

使用 fig.tight_layout() 减少灰色但不会删除它.

from matplotlib import pyplot as plty = [1,3,5,6,7,8,12,13,15,15,16,25,26,28,29,36]x = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]无花果，ax = plt.subplots(figsize =(8,4)，dpi = 85)ax.stackplot(x, y, color='w', colors=('#ededed',))ax.xaxis.set_visible(False)ax.yaxis.set_visible(False)ax.set_ylim([0,max(y)*1.2])ax.set_xlim([0,30])plt.show()

解决方案

指定创建 Axes 时， Axes 占据了整个 Figure .代码>-

  fig = plt.figure()ax = fig.add_axes((0,0,1,1), frameon=False)ax.plot([2,5,4])

现在，很多地方都没有空间了，例如外部刻度标签；Tkinter可能会自己做一些填充操作；但这与您可以制作Axes 一样大.( (0,0,1,1) 是图形坐标中的范围.)

How can I extend the plot area to take up the whole canvas and essentially remove the gray area in the image? I've looked around and I haven't found any solutions, although maybe it's because I don't know what to call that area so searching is challenging.

Using fig.tight_layout() reduces the gray but does not remove it.

from matplotlib import pyplot as plt

y = [1,3,5,6,7,8,12,13,15,15,16,25,26,28,29,36]
x = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
fig, ax = plt.subplots(figsize=(8,4), dpi=85)

ax.stackplot(x, y, color='w', colors=('#ededed',))

ax.xaxis.set_visible(False)
ax.yaxis.set_visible(False)
ax.set_ylim([0,max(y)*1.2])
ax.set_xlim([0,30])

plt.show()

解决方案

Specify that the Axes take up the whole Figure when you create the Axes --

fig = plt.figure()
ax = fig.add_axes((0,0,1,1), frameon=False)
ax.plot([2,5,4])

now, there's a lot there isn't room for any more, e.g. external tick labels; and Tkinter may be doing some padding itself; but this is as large as you can make an Axes. ( (0,0,1,1) is extent in Figure coordinates.)

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