具有多个元素的数组的真值是不明确的错误?Python [英] The truth value of an array with more than one element is ambiguous error? python

问题描述

from numpy import *
from pylab import *
from math import *

def TentMap(a,x):
    if x>= 0 and x<0.5:
        return 2.*a*x
    elif x>=0.5 and x<=1.:
        return 2.*a*(1.-x)

# We set a = 0.98, a typical chaotic value
a = 0.98
N = 1.0

xaxis = arange(0.0,N,0.01)

Func = TentMap

subplot(211)

title(str(Func.func_name) + ' at a=%g and its second iterate' %a)
ylabel('X(n+1)') # set y-axis label
plot(xaxis,Func(a,xaxis), 'g', antialiased=True)

subplot(212)

ylabel('X(n+1)') # set y-axis label
xlabel('X(n)')   # set x-axis label
plot(xaxis,Func(a,Func(a,xaxis)), 'bo', antialiased=True)  

我的 TentMap 功能无法正常工作.我不断收到错误具有多个元素的数组的真值不明确.使用a.any()或a.all()我不明白我应该如何使用它们.基本上， TentMap 函数采用值X，并根据X是什么而返回某个值.因此，如果 0<=x<0.5，则返回 2ax，如果 0.5<=x<=1，则返回 2a(1-x).

My TentMap function isn't working properly. I keep getting the error The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() I don't understand how I'm supposed to use those. Basically, the TentMap function takes a value X and returns a certain value depending on what X is. So if 0<=x<0.5 then it returns 2ax and if 0.5<=x<=1 then it returns 2a(1-x).

推荐答案

您可以使用 np.vectorize 来解决此错误，该错误在将 and 与标量一起使用时发生价值和误入歧途.通话看起来像

You can use np.vectorize to get around this error which occurs when using and with a scalar value and arrray. The call looks like

np.vectorize(TentMap)(a,xaxis)

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