如何将成员函数传递给另一个成员函数? [英] How to pass a member function to another member function?

问题描述

我的问题是将 A 类的成员函数传递给 B 类的成员函数:

My problem is about passing a member function from a Class A, to a member function of a Class B:

我尝试过这样的事情:

typedef void (moteurGraphique::* f)(Sprite);
f draw =&moteurGraphique::drawSprite;
defaultScene.boucle(draw);

moteurGraphique 是一个类，moteurGraphique::drawSprite 是一个成员函数，

moteurGraphique is A class, moteurGraphique::drawSprite is A member function,

defaultScene是B类的一个实例，boucle是B类的成员函数.

defaultScene is an instance of B class, and boucle is B member function.

在 A 的成员函数中调用的所有内容:

All that is called in a member function of A:

void moteurGraphique::drawMyThings()

我尝试了不同的方法来做到这一点，对我来说那种方法似乎更合乎逻辑，但它行不通！我得到:

I tried different ways to do it, that one seems the more logical to me, but it won't work! I got:

Run-Time Check Failure #3 - The variable 'f' is being used without being initialized.

我认为我做错了什么，有人可以解释我的错误吗?

I think I am doing something wrong, can someone explain my mistake ?

推荐答案

C++11 方式:

using Function = std::function<void (Sprite)>;

void B::boucle(Function func);
...

A a;
B b;

b.boucle(std::bind(&A::drawSprite, &a, std::placeholders::_1));

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