如何在C中释放二维数组? [英] How to free 2d array in C?

问题描述

我有以下代码:

int **ptr = (int **)malloc(sizeof(int*)*N); 
for(int i=0;i<N;i++) 
     ptr[i]=(int*)malloc(sizeof(int)*N));

如何使用 free 释放 ptr?我应该循环 ptr 并释放 ptr[i] 还是我应该做

How can I free ptr using free? Should I loop over ptr and free ptr[i] or should I just do

free(ptr) 

和ptr会被释放吗?

推荐答案

您将必须循环 ptr[i]，释放您遍历的每个 int*，正如您最初建议的那样.例如:

You will have to loop over ptr[i], freeing each int* that you traverse, as you first suggest. For example:

for (int i = 0; i < N; i++)
{
    int* currentIntPtr = ptr[i];
    free(currentIntPtr);
}

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