有没有办法通过一个匿名数组在C ++中的说法？ [英] Is there any way to pass an anonymous array as an argument in C++?

问题描述

我希望能够，申报一个数组在C函数参数++中所示的例子code以下（不编译）。有没有办法做到这一点（除另行声明数组事前）？

 的#include＆LT;＆stdio.h中GT;静态无效PrintArray（INT arrayLen，const int的*数组）
{
   的for（int i = 0; I＆LT; arrayLen;我++）的printf（％I  - ＆GT;％I \\ N，我，阵列[我]）;
}INT主（INT，CHAR **）
{
   PrintArray（5，{5,6,7,8,9}）; //不能编译
   返回0;
}
 

解决方案

没有。这不是由标准允​​许的。 匿名阵你指的实际上是一个的初始化列表的。初始化列表将被正式承认为C ++ 0x中的对象。现在，他们只是初始化C-阵列和POD类型语法。

例如，下面也不起作用：

  INT的main（）
{
    INT * P;
    P = {1，2，3}; //无效C或C ++
}
 

编辑：现在，C ++ 11已经出来了，这可以与内置的 initializer_list 键入完成。耶！

I'd like to be able to declare an array as a function argument in C++, as shown in the example code below (which doesn't compile). Is there any way to do this (other than declaring the array separately beforehand)?

#include <stdio.h>

static void PrintArray(int arrayLen, const int * array)
{
   for (int i=0; i<arrayLen; i++) printf("%i -> %i\n", i, array[i]);
}

int main(int, char **)
{
   PrintArray(5, {5,6,7,8,9} );  // doesn't compile
   return 0;
}

解决方案

No. This is not allowed by the standard. The "anonymous array" you refer to is actually an initializer list. Initializer lists will be formally recognized as objects in C++0x. For now, they are just a syntax for initializing c-arrays and POD types.

For example, the following also does not work:

int main()
{
    int* p;
    p = {1, 2, 3}; // not valid C or C++
}

EDIT: Now that C++11 is out, this can be done with the built-in initializer_list type. Yay!

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