跳过C ++函数一些参数？ [英] Skip some arguments in a C++ function?

问题描述

我有一个具有5个参数，都具有默认值的C ++函数。如果我首次通过三个参数，程序将默认值分配给最后两个参数。有什么办法来传递3个参数，并跳过一个在中间，让价值观说，第一，第二和第五个参数？

I have a C++ function that has 5 arguments, all of which have default values. If I pass in the first three arguments, the program will assign a default value to the last two arguments. Is there any way to pass 3 arguments, and skip one in the middle, giving values to say, the first, second, and fifth arguments?

推荐答案

不是直接的，但你也许能够做一些事情的std ::绑定：

Not directly, but you might be able to do something with std::bind:

int func(int arg1 = 0, int arg2 = 0, int arg3 = 0);

// elsewhere...
using std::bind;
using std::placeholders::_1;
auto f = bind(func, 0, _1, 0);

int result = f(3); // Call func(0, 3, 0);

缺点当然是你重新指定默认参数。我敢肯定，别人会用更聪明的解决方案一起走，但如果你真的绝望，这可能工作。

The downside is of course that you are re-specifying the default parameters. I'm sure somebody else will come along with a more clever solution, but this could work if you're really desperate.

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