集类型的可变长度参数列表 [英] Variable length argument list of set type

问题描述

好吧，我是pretty肯定，这已经在一些这样或那样讨论过，但我显然太愚蠢找到它。

Alright, I'm pretty sure that this has been discussed before in some way or another, but I'm apparently too stupid to find it.

第一：我不是在寻找va_list的另一个宏。
我所寻找的是类似主函数的参数。

First: I'm NOT looking for va_list and the other macros. What I am looking for is something like the main-function parameters.

默认的原型，因为所有你知道的是：

The default prototype, as all of you know is:

int main(int argc, char *argv[]);

现在，我要为我的程序类似的东西，但不知道究竟怎么了。

Now, I want something similar for my program, but don't know how exactly.

让我们假设有这样的功能：

Let's assume we have this function:

void Function(int argc, unsigned short *args[]) {
    for(int i = 0; i < argc; ++i) printf("%hu ", args[i]);
}

和我想是这样的函数调用：

And I want something like this function call:

Function(5, 1, 2, 3, 4, 5);

将这项工作？
因为我不想在混乱的va_list的，我也不想要创建：

Would that work? Because I don't want the 'cluttering' of va_list, nor do I want to create:

void AnotherFunction() {
    unsigned short Args[] = { 1, 2, 3, 4, 5 };
    Function(5, Args);
}

很简单，因为在这种情况下我只需要一个简单的指针。
可能有人请点我朝着正确的方向？非常感谢你。

Simply because in that case I would only need a simple pointer. Could someone please point me in the right direction? Thank you very much.

编辑：
谢谢大家对您的宝贵意见。我会满足于不标准的C / C ++，现在的工作，并寻找一个不同的方法来我的问题。

Thank you everyone for your valuable input. I'll settle for 'Doesn't work with standard C/C++ for now and look for a different approach to my problem.

再次非常感谢你。

推荐答案

一个g ++的特定解决方案：

A g++ specific solution:

const size_t MAX_ARGS = 42;

void Function(int argc, const unsigned short (&args)[MAX_ARGS])
{
}

int main()
{
    Function(5, {1,2,3,4,5});
}

如果你实际上并不需要的 ARGC 参数，你可以写一个模板：

If you don't actually need the argc parameter, you can write a template:

template<size_t N>
void Function(const unsigned short(&args)[N])
{
    // use N
}

这工作在C ++ 03。数组必须是const，否则你不能传递一个临时的初始化列表这样。如果您需要修改函数内部的元素，你需要进行复印。

This works in C++03. The array needs to be const, or else you can't pass a temporary initializer list like that. If you need to modify the elements inside the function, you'll need to make a copy.

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