引用传递字符串参数为一个bash脚本 [英] Passing quoted string arguments to a bash script

问题描述

我一直没能在这里或其他地方找到一个解决这个看似简单的问题。我想在嵌套目录中的所有文件的路径，在bash脚本添加引号在他们身边，并遍历它们。目录名和文件可以在他们的空格。到目前为止，我没有尝试过正常工作。带引号的路径字符串总是在空格就会破碎。

I have not been able to find a solution to this seemingly simple problem here or anywhere else. I want to get the paths of all files in a nested directory, add quotes around them, and loop through them in a bash script. Directory names and files can have white spaces in them. So far nothing I tried works properly. The quoted path strings always get broken up at the spaces.

test.sh

for var in "$@"
do
    echo "$var"
done

我想从文件中读取每行一个路径，单引号和双引号：

I tried reading from a file with one path per line, both single and double quotes:

find "nested directory with spaces" -type f | sed -e 's/^/"/g' -e 's/$/"/g' | tr '\n' '\n' > list.txt # double quotes
./test.sh `cat list.txt`

find "nested directory with spaces" -type f | sed -e 's/^/'\''/g' -e 's/$/'\''/g' | tr '\n' ' ' > list.txt # single quotes
./test.sh `cat list.txt`

和带引号的路径，单引号和双引号之间的空间命令替换：

and command substitution with a space between quoted paths, single and double quotes:

./test.sh `find "nested directory with spaces" -type f | sed -e 's/^/"/g' -e 's/$/"/g' | tr '\n' ' '` # double quotes

./test.sh `find "nested directory with spaces" -type f | sed -e 's/^/'\''/g' -e 's/$/'\''/g' | tr '\n' ' '` # single quotes

仅仅附和在命令行中带引号的路径给出期望的结果。现在缺少的脚本，它可以解决参数到完整的字符串？

Simply echoing a quoted path from the command line gives the desired result. What is missing in the script that can resolve the arguments into complete strings?

推荐答案

像这样做，而不是：

find "nested directory with spaces" -type f -exec ./test.sh {} +

这将调用 test.sh 使用多个参数，在不分裂名的空间。

This will call test.sh with multiple arguments, without splitting the spaces in the filenames.

如果你的版本找到不支持 + ，那么你可以使用 \\; 代替，但将调用 ./ test.sh 一次为每个参数

If your version of find doesn't support +, then you can use \; instead, but that will call ./test.sh once for each argument.

例如，给出脚本：

#!/bin/sh
echo start
for i; do
    echo file: "$i"
done

+ 和之间的区别\\; ：

$ find a\ b.txt date.txt -exec ./test.sh {} +
start
file: a b.txt
file: date.txt
$ find a\ b.txt date.txt -exec ./test.sh {} \;
start
file: a b.txt
start
file: date.txt

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