SQL 时间列不按升序排序 [英] SQL time column does not sort in ascending order

问题描述

我在尝试编写一个按时间列排序的 SQL 语句时遇到了一些麻烦，该列是 varchar 格式的升序.这是我的 SQL 语句:

I was having some trouble when trying to write an SQLstatement which sorted by time column which is in varchar format in ascending order. Here is my SQL statement:

SELECT mrtpopTime, mrtpopAmt
FROM tm_mrtpop
WHERE mrtpopName = ''
ORDER BY mrtpopTime

我得到了这些结果:

从图片中可以看出，它是按字符排序的.反正有没有像这样排序:

As you can see from the picture, it was sorted by character by character. Is there anyway to sort it like:

0:00, 1:00, 2:00, 3:00 all the way to 23:00

有什么想法吗?提前致谢.

Any ideas? Thanks in advance.

推荐答案

将 varchar 时间列转换为 time(或虚拟日期加时间)并按此排序:

Convert varchar time column to a time (or dummy date plus time) and order by that:

SELECT mrtpopTime, mrtpopAmt
FROM tm_mrtpop
WHERE mrtpopName = ''
ORDER BY STR_TO_DATE(mrtpopTime, '%H:%i')

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