无法使用准备好的语句从数据库中提取密码哈希 [英] Unable to extract password hash from database with prepared statements

问题描述

澄清一下，我无法使用准备好的语句从我的数据库中提取散列密码.

To clarify, I am unable to extract the hashed password from my database using prepared statements.

我正在尝试创建一个使用准备好的语句、password_hash 和 password_verify 的登录系统.

I'm trying to create a login system that uses prepared statements, password_hash and password_verify.

我已经创建了用于创建用户的注册表单，使用 password_hash($_POST['password'], PASSWORD_DEFAULT);

I have created the registering form that creates the user, with the hashed password using password_hash($_POST['password'], PASSWORD_DEFAULT);

这可以正常工作.

但是，我现在坚持创建登录表单.

However, I am now stuck on creating the login form.

我正在尝试获取在用户注册时存储的密码哈希，但我无法让它与准备好的语句一起使用.

I am trying to get the password hash that gets stored when a user registers but I cannot get it to work with prepared statements.

这是我目前拥有的.

<?php
require('db.php');

if(isset($_POST['submit'])) {
  $stmt = $connect->prepare('SELECT user_name, user_password FROM `users` WHERE user_name = ?');

  if($stmt) {
    $username = $_POST['username'];
    $password = $_POST['password'];

    $stmt->bind_param('s', $username);

    $stmt->execute();

  }
}

?>

如何使用从选择查询中获得的数据?以及如何使用它来验证密码?

How do I use the data that I got from the select query? And how do I use it to verify the password?

我试过了:

$stmt->store_result();
$stmt->bind_result($loginUsername, $hash);

那只存储了用户名，但没有存储密码哈希，我不知道为什么.

That only stored the username, but not the password hash and I have no clue why.

验证密码会用到这个吗?password_verify($password, $hash);

Verifying the password would use this? password_verify($password, $hash);

更新

<?php
require('db.php');

if(isset($_POST['submit'])) {
  $stmt = $connect->prepare('SELECT user_name, user_password FROM `users` WHERE user_name = ?');

  if($stmt) {
    $username = $_POST['username'];
    $password = $_POST['password'];

    $stmt->bind_param('s', $username);

    $stmt->execute();

    // Get query results
    $result = $stmt->get_result();

    // Fetch the query results in a row
    while($row = $result->fetch_assoc()) {
      $hash = $row['user_password'];
      $username = $row['user_name'];
    }

    // Verify user's password $password being input and $hash being the stored hash
    if(password_verify($password, $hash)) {
      // Password is correct
    } else {
      // Password is incorrect
    }

  }
}

?>

推荐答案

阅读此内容 PHP 手册.试试这个:

Read this PHP MANUAL.Try this:

 <?php
    require('db.php');

    if(isset($_POST['submit'])) {
      $stmt = $connect->prepare('SELECT user_name, user_password FROM `users` WHERE user_name = ?');

      if($stmt) {
        $username = $_POST['username'];
        $password = $_POST['password'];

        $stmt->bind_param('s', $username);

        $stmt->execute();

        // Get query results
        $stmt->bind_result($user_name,$hash);
        $stmt->store_result();

        // Fetch the query results in a row
        $stmt->fetch();

        // Verify user's password $password being input and $hash being the stored hash
        if(password_verify($password, $hash)) {
          // Password is correct
        } else {
          // Password is incorrect
        }

      }
    }

    ?>

这是我创建登录系统的方式:

This is how I created my login system:

$stmt = mysqli_prepare($link,"SELECT user_email,user_password,user_firstname,user_lastname,user_role,username FROM users WHERE user_email=?");
        mysqli_stmt_bind_param($stmt,"s",$email);
        mysqli_stmt_execute($stmt);
        confirmQuery($stmt);
        mysqli_stmt_bind_result($stmt,$user_email,$user_password,$user_firstname,$user_lastname,$user_role,$username);
        mysqli_stmt_store_result($stmt);
        mysqli_stmt_fetch($stmt);
        if(mysqli_stmt_num_rows($stmt) == 0)
            relocate("../index.php?auth_error=l1");
        else{
            if(password_verify($password,$user_password)){
                $_SESSION['userid'] = $user_email;
                $_SESSION['username'] = $username;
                $_SESSION['firstname'] = $user_firstname;
                $_SESSION['lastname'] = $user_lastname;
                $_SESSION['role'] = $user_role;
                if(isset($_POST['stay-logged-in']))
                    setcookie("userid", $email, time() + (86400 * 30), "/");
                relocate("../index.php?auth_success=1");
            }else
                relocate("../index.php?auth_error=l2");
        }
        mysqli_stmt_close($stmt);

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